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5t^2-8t-1.5=0
a = 5; b = -8; c = -1.5;
Δ = b2-4ac
Δ = -82-4·5·(-1.5)
Δ = 94
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-\sqrt{94}}{2*5}=\frac{8-\sqrt{94}}{10} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+\sqrt{94}}{2*5}=\frac{8+\sqrt{94}}{10} $
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